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  • Bunuel wrote:If 4 is one solution of the equation x^2 + 3x + k = 10, where k is a constant, what is the other solution?(A) -7(B) -4(C) -3(D) 1(E) 6Since 4 is one of the solution, so it must satisfy the equation.Putting 4 as value of x: 4^2 + 3*4 + k = 10 => k =-18so the equations is x^2 + 3x - 28 = 0Solving this by factorization gives => (x-4)(x+7) = 0So x = -7 is other solution.Hence A __________
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