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  • SOLUTIONIf 4 is one solution of the equation x^2 + 3x + k = 10, where k is a constant, what is the other solution?(A) -7(B) -4(C) -3(D) 1(E) 6Viete's formula for the roots \(x_1\) and \(x_2\) of equation \(ax^2+bx+c=0\): \(x_1+x_2=-\frac{b}{a}\) AND \(x_1*x_2=\frac{c}{a}\).Rewrite the equation given: \(x^2 + 3x +(k-10) =0\)Thus according to the first property \(4+x_2=-\frac{3}{1}\) --> \(x_2=-7\).
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