If the largest of these integers is 150, what is the least possible value of the smallest integer? * 1 * 2 * 12 * 53 * 100D, Let the numbers be a,b,c and dthen \(\frac{a+b+c+d}{4}\) \(= 125\)a+ b+c +d = 500 d = 150a+b+c= 350now 150 is the largest among the lot, then let c= 149 and b = 148 then equation becomesa+ 148+ 149 = 350 or a = 53 saorabh Manager Joined: 29 Oct 2009 Posts: 66 Followers: 1 Ku