| http://www.w3.org/ns/prov#value | - One lets P = sqrt(A A^*) (I think)and then A = O P , where O is an isometry or a partialisometry and P is a so-called positive operator.This might seem like a promising divide-and-conquerapproach to the invariant sub-space problem, butit does not seem to say much about what happens when,starting with a non-zero x in H, one iteratesA, constructing Ax, AAx, A^3 x, etc or usingthe polar decompositio
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