About: http://webisa.webdatacommons.org/176191130

Property	Value
http://www.w3.org/1999/02/22-rdf-syntax-ns#type	http://www.w3.org/ns/prov#Entity
http://www.w3.org/ns/prov#value	Now, as I understand it, 'p' is a point in 3D space, (x,y,z), so how is it possible to square the point and have it equal the radius squared?
http://www.w3.org/ns/prov#wasQuotedFrom	stackexchange.com