| http://www.w3.org/ns/prov#value | - I am not one of the 20 by any means.In a nutshell f=m.a+drags And p=f.v so a=(p/v-drags)/m so for a given m and v and drags, to maximise a at that exact situation you need to maximise p. drags is an all encompassing term to cover losses (aero, rr, driveline) at that speed.The confusing argument is as follows.f=m.a+dragsf=T.grwhere T is the instantaneous engine torque and gr is the overall gear rati
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