About: http://webisa.webdatacommons.org/196954674

Property	Value
http://www.w3.org/1999/02/22-rdf-syntax-ns#type	http://www.w3.org/ns/prov#Entity
http://www.w3.org/ns/prov#value	which shows that $a_{p+1}^!f = 0 = j_{p}^!f$ implies $a_p^!f = 0$ (it is this implication that I do not understand, related to my confusion is an earlier question of mine Showing morphism of sheaves is zero )
http://www.w3.org/ns/prov#wasQuotedFrom	mathoverflow.net