| http://www.w3.org/ns/prov#value | - It also arises with the cooling of a cup of tea, where by Newton's law of cooling, the rate at which the tea cools is proportional to the difference in temperature between the tea and the surrounding room: if T is the temperature of the tea, T0 is the temperature of the room, and t is the time, then dT/dt, the rate of cooling, is -K(T - T0), where K is a constant.
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