| http://www.w3.org/ns/prov#value | - Furthermore these are going to be proper subsets; if we have that 7, 11, and 13 are prime factors of k and none of those are prime factors of k+1, or vice versa, then we get that k does not in fact have three digits.So we can have the following six situations:(1) k is a multiple of 7 and k + 1 is a multiple of 143;(2) k is a multiple of 11 and k + 1 is a multiple of 91;(3) k is a multiple of 13 and
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