| http://www.w3.org/ns/prov#value | - In this case, assuming that L is a component also enclosed with ??1 and ??2 and that U is a component also enclosed with ??1, the processing of ???2 , ???4 , ???5 is executed for L=L and U=U without considering the holes of D1, C.sub. 1, and, C2, thereby defining {Ci } and {Dj } again as {Ci '} and {Dj '} (FIG. 6D).
|
