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http://webisa.webdatacommons.org/284735923
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@blochwave constantpart = Pi/n^2 Sum[Sum[Exp[-Abs[x[[j]] - x[[i]]]], {i, 1, n}], {j, 1, n}] and evaluates to 2.51838 x is a sample of an exponential distribution with lamda = 4, so mean 1/4. n=10000
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