| http://www.w3.org/ns/prov#value | - 23 Jan 2010, 21:09 Tadashi wrote:What is the area of parallelogram \(ABCD\)?1. \(AB = BC =CD = DA = 1\)2. \(AC = BD = \sqrt{2}\)I thought that the answer is B, since if AC and BD are equal, and since the shape is a parallelogram then it would be square making the area findable?
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