| http://www.w3.org/ns/prov#value | - Forming the scalar product, we obtain p E + p E = m 0 2 ( g 2 c 2 g 2 v N 2 ) = m 0 2 c 2 because v E + v E = c 2 Multiplying throughout by c 2 and rearranging, we find m 0 2 c 4 = g 2 m 0 2 c 4 g 2 m 0 2 c 2 v N 2 We see that g is a number and therefore g multiplied by the rest mass m 0 is a mass ; let us therefore denote it by m: m = g m 0 the relativistic mass.
|
