| http://www.w3.org/ns/prov#value | - 10 Jun 2012, 13:18 If n is a positive integer, is n^3 - n divisible by 4? (1) n = 2K + 1, where k is an integer (2) n^2 + n is divisible by 6 Vote for A(A) n = 2K + 1 therefore n = {1,3,5,7,9,11 ......}when n=3 then 3(9-1) is divisible by 4 sufficient all values of n = {1,3,5,7,9,11 ......} will be divisiable by 4Information sufficent(B) n^2 + n is divisible by 6 n(n+1) = 6q (q = any multiple of 6
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