| http://www.w3.org/ns/prov#value | - 04 Apr 2006, 03:23 HongHu wrote:Basically you write the two conditions:n=7a+3n=4b+2Therefore 4b=7a-1=8a-a-1b=2a-(a-1)/4We know that b is an integer so (a-1)/4 must be an integer.We can write as a-1=4s, or a=4s+1.Now we knowa=4s+1,b=2(4s+1)-s=7s+2You can solve for n here from either a or b, although you do not have to.
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