| http://www.w3.org/ns/prov#value | - We can see this if we take k = 12, and subtract 6 from the sum:(We do not need to do any scaling to get the variance equal to one in value - remember that the variance of a U[0 , 1] variable is 1/12, and we are summing 12 independent such variables.)Of course, there are much better ways than this to generate Normal variates, but I will not go into that here.There is an interesting, more general, questio
|
