| http://www.w3.org/ns/prov#value | - 31 May 2009, 05:03 As n is a positive integer, 5n would be a multiple of 5 and unit digit will always be either 5 or 0Now consider the possible scenariosWhen the unit digit of 5n is 5,56 - x5 = y1 (x and y can be anything here, we are just concerned with unit digit)x5 - 56 = y9 When the unit digit of 5n is 0,56 - x0 = y6 x0 - 56 = y4With both these conditions we have only four possibles values of
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