PropertyValue
http://www.w3.org/1999/02/22-rdf-syntax-ns#type
http://www.w3.org/ns/prov#value
  • For the second part, divide the $k$ people into $k/2=n+1$ pairs and let the two people in each pair not be friends, while everybody is a friend with all those people they are not paired with.
http://www.w3.org/ns/prov#wasQuotedFrom
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