| http://www.w3.org/ns/prov#value | - (b) To begin with, if I want to show that something is a subgroup, I have to show that: (i)$ a,b \in U \Rightarrow a \circ b \in U$ and that (ii)$a \in U \Rightarrow a^{-1} \in U$ correct? (I am actually a little confused at why we can just assume that the identity element is still part of a subgroup, for instance if the exercise were a little different and I was checking if $A_{n} = \{ au \in S_{
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