| http://www.w3.org/ns/prov#value | - If instead we used a potential of g??? (x, y, z)=K???g (x, y, z), where K is a constant, then we would have pot1???=K and pot2???=2???K. The decision would still be zone 2, since pot2???>pot1??? and the confidence level would be conf 2 ??? = pot 2 ??? pot 1 ??? + pot 2 ??? = K ??? pot 2 ??? ( K ??? pot 1 ??? ) + ( K ??? pot 2 ??? ) = conf 2 .
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