| http://www.w3.org/ns/prov#value | - Is x ??? y + 1 greater than x + y ??? 1? (1) x > 0 (2) y < 0I saw a reply somewhere that simplifies the given equation as:x ??? y + 1 > x + y ??? 1 (Canceling xon both sides)y < 1But my question is how we can cancel x as we do not know whether x is positive or negative? [Reveal]
|
