| http://www.w3.org/ns/prov#value | - So if it is not 180 miles around it is a big peanut- and earth is the most dense object in the solar system @ 5.52 g/cm^3 so if it was just as dense as earth (not likely) and the size of Ceres 950 km in diameter gives the equation :(6.67300 * 10^-20 (km^3) (kg^(-1)) (s^(-2)))*((3 537 952 kg/151.197196 km^2) for surface gravity = 1.0327 * 10^-14 m / s2 which is 0.00000000000000105% of the surface gr
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