| http://www.w3.org/ns/prov#value | - If n is a positive integer, is n3 ??? n divisible by 4 ?(1) n = 2k + 1, where k is an integer.(2) n2 + n is divisible by 6.If n is a positive integer, is n^3 ??? n divisible by 4 ?n^3-n=n(n^2-1)=(n-1)n(n+1), so we are asked whether the product of 3 consecutive integers is divisible bu 4.(1) n = 2k + 1, where k is an integer --> n=odd --> as n is odd then both n-1 and n+1 are even hence (n-1)n(n+1)
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