| http://www.w3.org/ns/prov#value | - If n is a positive integer, is n^3 - n divisible by 4?(1) n = 2k+1, where k is an integer(2) n^2 + n is divisible by 6I actually got this answer wrong, but wanted to ask the forum if my thinking is incorrect.So here was my thought process.n^3 - n = n(n^2 -n) = n(n+1)(n-1), so if n is odd and greater than 1, then the equation is divisible by 4.For (1), n can be 3 if k=1, but n can be 1 if k=0, sinc
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