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http://webisa.webdatacommons.org/216838988
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This means that there exists an orthonormal basis such that both $S$ and $T$ are diagonal with respect to that basis, i.e. every vector in such a basis is a common eigenvector. share|improve this answer answered Apr 16 '12 at 13:48
http://www.w3.org/ns/prov#wasQuotedFrom
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