| http://www.w3.org/ns/prov#value | - friend of D and E (1 relationship), D is a friend of E and C, (2nd relationship) E is a friend of C and D(3rd relationship)) So we have 3 relationships in total that satisfy the above criteria =3The probability that the two random individuals are friends =(3+2)/21 =5/21The probability that the two random individuals chosen are not friends = 1- (5/21) UMB Senior Manager Joined: 28 Feb 2007 Posts: 3
|
